1/2x^2-5x+19/2=0

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Solution for 1/2x^2-5x+19/2=0 equation: 


x in (-oo:+oo)

(1/2)*x^2-(5*x)+19/2 = 0

(1/2)*x^2-5*x+19/2 = 0

1/2*x^2-5*x+19/2 = 0

DELTA = (-5)^2-(1/2*4*19/2)

DELTA = 6

DELTA > 0

x = (6^(1/2)+5)/(1/2*2) or x = (5-6^(1/2))/(1/2*2)

x = 6^(1/2)+5 or x = 5-6^(1/2)

x in { 5-6^(1/2), 6^(1/2)+5 }

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